Introduction:
This project, titled "Inverter Circuit Using NE 555 IC," details the creation of an emergency inverter circuit utilizing commonplace components like the NE-555 IC and a 0-12V/220V step-down transformer. This circuit is particularly useful during emergencies and provides maximum output to power LED bulbs. Let's explore how to construct the circuit below.
Connection:
IC Base and NE-555 IC:
- Begin by soldering the IC base with the NE-555 IC onto a DOT board.
Resistors and Capacitors:
- Solder two 10K resistors in series on the left side of the IC. Connect the first pin of the first 10K resistor to the positive side of the power supply. Then, connect the second pin of the second 10K resistor to the positive side of a 1µF capacitor. Connect the capacitor's negative pin to the negative side of the power supply.
Connecting NE-555 Pins:
- Connect the IC's 7th pin to the center of the two 10K resistors. Additionally, connect the IC's 2nd and 6th pins to the positive side of the 1µF capacitor.
- Connect the IC's 1st pin to the negative side of the power supply, and connect the 4th and 8th pins to the positive side of the power supply.
Resistor and MOSFET:
- Connect the first pin of a 1K resistor to the IC's 3rd pin, and the resistor's second pin to the MOSFET's first pin.
- Connect the secondary winding's first wire of the step-down transformer to the MOSFET's second pin, and connect the other wire of the secondary winding to the positive side of the power supply.
- Finally, connect the MOSFET's third pin to the negative side of the power supply. The primary winding wires of the transformer serve as the output points, completing the circuit.
Note
Ensure the circuit board is clean before testing due to the high voltage involved. Avoid touching the primary winding wire of the transformer to prevent electric shock.
Note:
Ensure the circuit board is clean before testing due to the high voltage. Avoid touching the primary winding wire of the transformer to prevent electric shock❗
Circuit Diagram:
Working:
In this circuit configuration, the IC 555 is set up as an astable multivibrator. It generates pulses at its 3rd pin with a frequency determined by the selected resistors and capacitor across its 2nd and 6th pins. These pulses are then fed to a MOSFET, which is connected to the 12V winding of a step-down transformer.
The IC 555, along with the transformer MOSFET driver, acts as a small DC to AC inverter, producing a 6V to 220V output. While the output is not precisely AC, lacking negative half cycles and delivering only half-wave pulsed 220V AC, it is sufficient to brightly illuminate a 10W LED light.
Therefore, this simple 12V inverter circuit efficiently and inexpensively enables the illumination of small LED bulbs from a 6V battery or any 6V DC power supply.
Parts List:
1) NE
555 IC =1
2) 8
Pin IC Base =1
3) IRF
Z44 MOSFET =1
4) 10KΩ
¼ W Resistor =2
5) 1KΩ
¼ W Resistor =1
6) 1µF
Capacitor =1
7) 0-12
Volt Step Down Transformer =1
8) DOT
Board =1
9) Some
Wires
10) 2 Pin Connector =1
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By,
G.Guruvel
Sarveshwar,
EEE Dept.
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